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20401423113 = 331263834107
BaseRepresentation
bin10011000000000001…
…010000001100001001
31221122210212200020110
4103000001100030021
5313240231014423
613212225144533
71321365143451
oct230001201411
957583780213
1020401423113
11871a087165
123b5448b149
131c018c6bc6
14db773ad61
157e6111193
hex4c0050309

20401423113 has 16 divisors (see below), whose sum is σ = 28186177536. Its totient is φ = 13112146320.

The previous prime is 20401423111. The next prime is 20401423123. The reversal of 20401423113 is 31132410402.

It is not a de Polignac number, because 20401423113 - 21 = 20401423111 is a prime.

It is a super-2 number, since 2×204014231132 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20401423113.

It is not an unprimeable number, because it can be changed into a prime (20401423111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 392595 + ... + 441512.

It is an arithmetic number, because the mean of its divisors is an integer number (1761636096).

Almost surely, 220401423113 is an apocalyptic number.

It is an amenable number.

20401423113 is a deficient number, since it is larger than the sum of its proper divisors (7784754423).

20401423113 is a wasteful number, since it uses less digits than its factorization.

20401423113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 834404.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 20401423113 its reverse (31132410402), we get a palindrome (51533833515).

The spelling of 20401423113 in words is "twenty billion, four hundred one million, four hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 3 31 93 263 789 8153 24459 834107 2502321 25857317 77571951 219370141 658110423 6800474371 20401423113