Base | Representation |
---|---|
bin | 1001010001110010000100… |
… | …00100000010110101010001 |
3 | 2200020102122121101111120122 |
4 | 10220321002010002311101 |
5 | 10133232202432344213 |
6 | 111220350452320025 |
7 | 4204003416146444 |
oct | 450710204026521 |
9 | 80212577344518 |
10 | 20402203012433 |
11 | 6556586797270 |
12 | 2356100613015 |
13 | b4cbc5169918 |
14 | 507686c4365b |
15 | 255a94d93d08 |
hex | 128e42102d51 |
20402203012433 has 4 divisors (see below), whose sum is σ = 22256948740848. Its totient is φ = 18547457284020.
The previous prime is 20402203012421. The next prime is 20402203012483. The reversal of 20402203012433 is 33421030220402.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20402203012433 - 212 = 20402203008337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20402203012483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 927372864191 + ... + 927372864212.
It is an arithmetic number, because the mean of its divisors is an integer number (5564237185212).
Almost surely, 220402203012433 is an apocalyptic number.
It is an amenable number.
20402203012433 is a deficient number, since it is larger than the sum of its proper divisors (1854745728415).
20402203012433 is a wasteful number, since it uses less digits than its factorization.
20402203012433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1854745728414.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 20402203012433 its reverse (33421030220402), we get a palindrome (53823233232835).
The spelling of 20402203012433 in words is "twenty trillion, four hundred two billion, two hundred three million, twelve thousand, four hundred thirty-three".
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