Base | Representation |
---|---|
bin | 1011111000000011011… |
… | …0000100110101010011 |
3 | 201111121212021002000212 |
4 | 2332000312010311103 |
5 | 11320320412402011 |
6 | 233421114234335 |
7 | 20511634631645 |
oct | 2760066046523 |
9 | 644555232025 |
10 | 204025122131 |
11 | 79587954016 |
12 | 3365b7259ab |
13 | 163161c854c |
14 | 9c368d4895 |
15 | 5491a0d08b |
hex | 2f80d84d53 |
204025122131 has 16 divisors (see below), whose sum is σ = 216283888800. Its totient is φ = 192117945600.
The previous prime is 204025122127. The next prime is 204025122139. The reversal of 204025122131 is 131221520402.
It is a cyclic number.
It is not a de Polignac number, because 204025122131 - 22 = 204025122127 is a prime.
It is a super-2 number, since 2×2040251221312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 204025122097 and 204025122106.
It is not an unprimeable number, because it can be changed into a prime (204025122139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3551585 + ... + 3608573.
It is an arithmetic number, because the mean of its divisors is an integer number (13517743050).
Almost surely, 2204025122131 is an apocalyptic number.
204025122131 is a deficient number, since it is larger than the sum of its proper divisors (12258766669).
204025122131 is a wasteful number, since it uses less digits than its factorization.
204025122131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60070.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 204025122131 its reverse (131221520402), we get a palindrome (335246642533).
The spelling of 204025122131 in words is "two hundred four billion, twenty-five million, one hundred twenty-two thousand, one hundred thirty-one".
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