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204025122131 = 2941301156989
BaseRepresentation
bin1011111000000011011…
…0000100110101010011
3201111121212021002000212
42332000312010311103
511320320412402011
6233421114234335
720511634631645
oct2760066046523
9644555232025
10204025122131
1179587954016
123365b7259ab
13163161c854c
149c368d4895
155491a0d08b
hex2f80d84d53

204025122131 has 16 divisors (see below), whose sum is σ = 216283888800. Its totient is φ = 192117945600.

The previous prime is 204025122127. The next prime is 204025122139. The reversal of 204025122131 is 131221520402.

It is a cyclic number.

It is not a de Polignac number, because 204025122131 - 22 = 204025122127 is a prime.

It is a super-2 number, since 2×2040251221312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 204025122097 and 204025122106.

It is not an unprimeable number, because it can be changed into a prime (204025122139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3551585 + ... + 3608573.

It is an arithmetic number, because the mean of its divisors is an integer number (13517743050).

Almost surely, 2204025122131 is an apocalyptic number.

204025122131 is a deficient number, since it is larger than the sum of its proper divisors (12258766669).

204025122131 is a wasteful number, since it uses less digits than its factorization.

204025122131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60070.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 204025122131 its reverse (131221520402), we get a palindrome (335246642533).

The spelling of 204025122131 in words is "two hundred four billion, twenty-five million, one hundred twenty-two thousand, one hundred thirty-one".

Divisors: 1 29 41 1189 3011 56989 87319 123451 1652681 2336549 3580079 67759921 171593879 4976222491 7035349039 204025122131