Base | Representation |
---|---|
bin | 1001010001110101011010… |
… | …01101000000000011000011 |
3 | 2200020121021212201110202011 |
4 | 10220322231031000003003 |
5 | 10133244343113204220 |
6 | 111221245103233351 |
7 | 4204066103553415 |
oct | 450725515000303 |
9 | 80217255643664 |
10 | 20404000522435 |
11 | 6557319400122 |
12 | 23565225a8857 |
13 | b501206974ca |
14 | 5077b786c9b5 |
15 | 255b4caa965a |
hex | 128ead3400c3 |
20404000522435 has 8 divisors (see below), whose sum is σ = 24660950272560. Its totient is φ = 16205767320864.
The previous prime is 20404000522421. The next prime is 20404000522457. The reversal of 20404000522435 is 53422500040402.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20404000522435 - 215 = 20404000489667 is a prime.
It is a super-3 number, since 3×204040005224353 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20404000522397 and 20404000522406.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14679136372 + ... + 14679137761.
It is an arithmetic number, because the mean of its divisors is an integer number (3082618784070).
Almost surely, 220404000522435 is an apocalyptic number.
20404000522435 is a deficient number, since it is larger than the sum of its proper divisors (4256949750125).
20404000522435 is a wasteful number, since it uses less digits than its factorization.
20404000522435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29358274277.
The product of its (nonzero) digits is 38400, while the sum is 31.
Adding to 20404000522435 its reverse (53422500040402), we get a palindrome (73826500562837).
The spelling of 20404000522435 in words is "twenty trillion, four hundred four billion, five hundred twenty-two thousand, four hundred thirty-five".
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