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204134513523 = 368044837841
BaseRepresentation
bin1011111000011101011…
…1010111101101110011
3201111220111002201210220
42332013113113231303
511321031413413043
6233440023024123
720514433510203
oct2760727275563
9644814081726
10204134513523
117963367a426
123369029b043
1316332a79895
149c4724c403
15549b41a483
hex2f875d7b73

204134513523 has 4 divisors (see below), whose sum is σ = 272179351368. Its totient is φ = 136089675680.

The previous prime is 204134513521. The next prime is 204134513533. The reversal of 204134513523 is 325315431402.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 204134513523 - 21 = 204134513521 is a prime.

It is a super-2 number, since 2×2041345135232 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (204134513521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34022418918 + ... + 34022418923.

It is an arithmetic number, because the mean of its divisors is an integer number (68044837842).

Almost surely, 2204134513523 is an apocalyptic number.

204134513523 is a deficient number, since it is larger than the sum of its proper divisors (68044837845).

204134513523 is an equidigital number, since it uses as much as digits as its factorization.

204134513523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68044837844.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 204134513523 its reverse (325315431402), we get a palindrome (529449944925).

The spelling of 204134513523 in words is "two hundred four billion, one hundred thirty-four million, five hundred thirteen thousand, five hundred twenty-three".

Divisors: 1 3 68044837841 204134513523