Base | Representation |
---|---|
bin | 1001010010101011101000… |
… | …11100111010100111011011 |
3 | 2200100101102210021220112100 |
4 | 10221111310130322213123 |
5 | 10134234003432224001 |
6 | 111242502000214443 |
7 | 4206146410125234 |
oct | 451256434724733 |
9 | 80311383256470 |
10 | 20433113164251 |
11 | 65686a8766887 |
12 | 23600a830a423 |
13 | b52aacc71098 |
14 | 508d7a0cc08b |
15 | 2567a3852586 |
hex | 12957473a9db |
20433113164251 has 6 divisors (see below), whose sum is σ = 29514496792820. Its totient is φ = 13622075442828.
The previous prime is 20433113164193. The next prime is 20433113164301. The reversal of 20433113164251 is 15246131133402.
20433113164251 is a `hidden beast` number, since 2 + 0 + 4 + 3 + 3 + 1 + 1 + 3 + 1 + 642 + 5 + 1 = 666.
It is not a de Polignac number, because 20433113164251 - 29 = 20433113163739 is a prime.
It is a super-2 number, since 2×204331131642512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20433113164151) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1135172953561 + ... + 1135172953578.
Almost surely, 220433113164251 is an apocalyptic number.
20433113164251 is a deficient number, since it is larger than the sum of its proper divisors (9081383628569).
20433113164251 is a wasteful number, since it uses less digits than its factorization.
20433113164251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2270345907145 (or 2270345907142 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 36.
Adding to 20433113164251 its reverse (15246131133402), we get a palindrome (35679244297653).
The spelling of 20433113164251 in words is "twenty trillion, four hundred thirty-three billion, one hundred thirteen million, one hundred sixty-four thousand, two hundred fifty-one".
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