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2043314113 = 17431117223
BaseRepresentation
bin111100111001010…
…0111111111000001
312021101212010000111
41321302213333001
513141042022423
6534431151321
7101430612001
oct17162477701
95241763014
102043314113
11959441155
12490375541
13267431509
14155532001
15be5bb60d
hex79ca7fc1

2043314113 has 4 divisors (see below), whose sum is σ = 2043448768. Its totient is φ = 2043179460.

The previous prime is 2043314111. The next prime is 2043314123. The reversal of 2043314113 is 3114133402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2043314113 - 21 = 2043314111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2043314111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41181 + ... + 76042.

It is an arithmetic number, because the mean of its divisors is an integer number (510862192).

Almost surely, 22043314113 is an apocalyptic number.

It is an amenable number.

2043314113 is a deficient number, since it is larger than the sum of its proper divisors (134655).

2043314113 is a wasteful number, since it uses less digits than its factorization.

2043314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134654.

The product of its (nonzero) digits is 864, while the sum is 22.

The square root of 2043314113 is about 45203.0321217504. The cubic root of 2043314113 is about 1268.9515626348.

Adding to 2043314113 its reverse (3114133402), we get a palindrome (5157447515).

The spelling of 2043314113 in words is "two billion, forty-three million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 17431 117223 2043314113