Base | Representation |
---|---|
bin | 1011111011010111100… |
… | …1001001011010111011 |
3 | 201120220212221122022121 |
4 | 2332311321021122323 |
5 | 11324131232313203 |
6 | 234045310102111 |
7 | 20542662531232 |
oct | 2766571113273 |
9 | 646825848277 |
10 | 204915119803 |
11 | 799a4274489 |
12 | 338697aa937 |
13 | 164286cc2a4 |
14 | 9cbcba9b19 |
15 | 54e4c110bd |
hex | 2fb5e496bb |
204915119803 has 4 divisors (see below), whose sum is σ = 204956380080. Its totient is φ = 204873859528.
The previous prime is 204915119771. The next prime is 204915119807. The reversal of 204915119803 is 308911519402.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 204915119803 - 25 = 204915119771 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 204915119803.
It is not an unprimeable number, because it can be changed into a prime (204915119807) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20622688 + ... + 20632621.
It is an arithmetic number, because the mean of its divisors is an integer number (51239095020).
Almost surely, 2204915119803 is an apocalyptic number.
204915119803 is a deficient number, since it is larger than the sum of its proper divisors (41260277).
204915119803 is an equidigital number, since it uses as much as digits as its factorization.
204915119803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41260276.
The product of its (nonzero) digits is 77760, while the sum is 43.
The spelling of 204915119803 in words is "two hundred four billion, nine hundred fifteen million, one hundred nineteen thousand, eight hundred three".
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