Base | Representation |
---|---|
bin | 11101110101011111100… |
… | …111001100110111100011 |
3 | 21021000012011210000211102 |
4 | 131311133213030313203 |
5 | 232043010144341120 |
6 | 4205521343505015 |
7 | 301062301205402 |
oct | 35653747146743 |
9 | 7230164700742 |
10 | 2050303512035 |
11 | 72058a976a29 |
12 | 2914425b816b |
13 | 11b45c1615cc |
14 | 71341629639 |
15 | 384ee326d75 |
hex | 1dd5f9ccde3 |
2050303512035 has 4 divisors (see below), whose sum is σ = 2460364214448. Its totient is φ = 1640242809624.
The previous prime is 2050303512029. The next prime is 2050303512043. The reversal of 2050303512035 is 5302153030502.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2050303512035 - 28 = 2050303511779 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2050303511989 and 2050303512007.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205030351199 + ... + 205030351208.
It is an arithmetic number, because the mean of its divisors is an integer number (615091053612).
Almost surely, 22050303512035 is an apocalyptic number.
2050303512035 is a deficient number, since it is larger than the sum of its proper divisors (410060702413).
2050303512035 is an equidigital number, since it uses as much as digits as its factorization.
2050303512035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 410060702412.
The product of its (nonzero) digits is 13500, while the sum is 29.
Adding to 2050303512035 its reverse (5302153030502), we get a palindrome (7352456542537).
The spelling of 2050303512035 in words is "two trillion, fifty billion, three hundred three million, five hundred twelve thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •