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205110143307 = 32149152953127
BaseRepresentation
bin1011111100000110000…
…1000110100101001011
3201121102110220212021100
42333001201012211023
511330031144041212
6234120514112443
720550551310666
oct2770141064513
9647373825240
10205110143307
1179a94368533
1233902b7b723
1316459c33404
149cdaa546dd
155506dd5bdc
hex2fc184694b

205110143307 has 12 divisors (see below), whose sum is σ = 298258599600. Its totient is φ = 135822375888.

The previous prime is 205110143279. The next prime is 205110143311. The reversal of 205110143307 is 703341011502.

205110143307 is a `hidden beast` number, since 2 + 0 + 511 + 0 + 143 + 3 + 0 + 7 = 666.

It is not a de Polignac number, because 205110143307 - 223 = 205101754699 is a prime.

It is not an unprimeable number, because it can be changed into a prime (205110193307) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 76475223 + ... + 76477904.

It is an arithmetic number, because the mean of its divisors is an integer number (24854883300).

Almost surely, 2205110143307 is an apocalyptic number.

205110143307 is a deficient number, since it is larger than the sum of its proper divisors (93148456293).

205110143307 is a wasteful number, since it uses less digits than its factorization.

205110143307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152953282 (or 152953279 counting only the distinct ones).

The product of its (nonzero) digits is 2520, while the sum is 27.

Adding to 205110143307 its reverse (703341011502), we get a palindrome (908451154809).

The spelling of 205110143307 in words is "two hundred five billion, one hundred ten million, one hundred forty-three thousand, three hundred seven".

Divisors: 1 3 9 149 447 1341 152953127 458859381 1376578143 22790015923 68370047769 205110143307