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2052350431435 = 54091447693569
BaseRepresentation
bin11101110111011001100…
…111100101000011001011
321021012110211102022101001
4131313121213211003023
5232111203202301220
64210500424235431
7301164104554423
oct35673147450313
97235424368331
102052350431435
1172144034a857
1229191400bb77
1311b6c7255b15
1471497419483
15385bdda680a
hex1ddd99e50cb

2052350431435 has 16 divisors (see below), whose sum is σ = 2470551825600. Its totient is φ = 1636731703296.

The previous prime is 2052350431429. The next prime is 2052350431493. The reversal of 2052350431435 is 5341340532502.

It is a cyclic number.

It is not a de Polignac number, because 2052350431435 - 23 = 2052350431427 is a prime.

It is a super-2 number, since 2×20523504314352 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2052350431394 and 2052350431403.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2612331 + ... + 3305899.

It is an arithmetic number, because the mean of its divisors is an integer number (154409489100).

Almost surely, 22052350431435 is an apocalyptic number.

2052350431435 is a deficient number, since it is larger than the sum of its proper divisors (418201394165).

2052350431435 is a wasteful number, since it uses less digits than its factorization.

2052350431435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 695430.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 2052350431435 its reverse (5341340532502), we get a palindrome (7393690963937).

The spelling of 2052350431435 in words is "two trillion, fifty-two billion, three hundred fifty million, four hundred thirty-one thousand, four hundred thirty-five".

Divisors: 1 5 409 1447 2045 7235 591823 693569 2959115 3467845 283669721 1003594343 1418348605 5017971715 410470086287 2052350431435