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2052453514051 = 14913774855799
BaseRepresentation
bin11101110111011111110…
…000110011101101000011
321021012202000101110010201
4131313133300303231003
5232111411044422201
64210514545510031
7301166466006013
oct35673760635503
97235660343121
102052453514051
117214935572a6
12291942642317
1311b712708755
14714a6dadc43
15385c7e69801
hex1dddfc33b43

2052453514051 has 4 divisors (see below), whose sum is σ = 2066228370000. Its totient is φ = 2038678658104.

The previous prime is 2052453514049. The next prime is 2052453514081. The reversal of 2052453514051 is 1504153542502.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2052453514051 - 21 = 2052453514049 is a prime.

It is a super-3 number, since 3×20524535140513 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2052453514051.

It is not an unprimeable number, because it can be changed into a prime (2052453514081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6887427751 + ... + 6887428048.

It is an arithmetic number, because the mean of its divisors is an integer number (516557092500).

Almost surely, 22052453514051 is an apocalyptic number.

2052453514051 is a deficient number, since it is larger than the sum of its proper divisors (13774855949).

2052453514051 is a wasteful number, since it uses less digits than its factorization.

2052453514051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13774855948.

The product of its (nonzero) digits is 120000, while the sum is 37.

The spelling of 2052453514051 in words is "two trillion, fifty-two billion, four hundred fifty-three million, five hundred fourteen thousand, fifty-one".

Divisors: 1 149 13774855799 2052453514051