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2053141401145 = 51373308390599
BaseRepresentation
bin11101111000001000110…
…000111000111000111001
321021021111221202201211111
4131320020300320320321
5232114313144314040
64211111121400321
7301222520650522
oct35701060707071
97237457681744
102053141401145
1172180688302a
12291ab4a990a1
1311b7c2096633
14715304b3849
1538618547dea
hex1de08c38e39

2053141401145 has 16 divisors (see below), whose sum is σ = 2481855811200. Its totient is φ = 1630456691584.

The previous prime is 2053141401137. The next prime is 2053141401161. The reversal of 2053141401145 is 5411041413502.

It is a cyclic number.

It is not a de Polignac number, because 2053141401145 - 23 = 2053141401137 is a prime.

It is a super-2 number, since 2×20531414011452 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22616556 + ... + 22707154.

It is an arithmetic number, because the mean of its divisors is an integer number (155115988200).

Almost surely, 22053141401145 is an apocalyptic number.

It is an amenable number.

2053141401145 is a deficient number, since it is larger than the sum of its proper divisors (428714410055).

2053141401145 is a wasteful number, since it uses less digits than its factorization.

2053141401145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123824.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 2053141401145 its reverse (5411041413502), we get a palindrome (7464182814647).

The spelling of 2053141401145 in words is "two trillion, fifty-three billion, one hundred forty-one million, four hundred one thousand, one hundred forty-five".

Divisors: 1 5 137 685 33083 90599 165415 452995 4532371 12412063 22661855 62060315 2997286717 14986433585 410628280229 2053141401145