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20535340153 = 71289230143
BaseRepresentation
bin10011001000000000…
…000110110001111001
31222000010212100212211
4103020000012301321
5314024021341103
613233411335121
71324612340236
oct231000066171
958003770784
1020535340153
118788733aa9
123b912b14a1
131c23584563
14dcb43a78d
15802c6536d
hex4c8006c79

20535340153 has 4 divisors (see below), whose sum is σ = 20824570368. Its totient is φ = 20246109940.

The previous prime is 20535340123. The next prime is 20535340159. The reversal of 20535340153 is 35104353502.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20535340153 - 233 = 11945405561 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20535340159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144615001 + ... + 144615142.

It is an arithmetic number, because the mean of its divisors is an integer number (5206142592).

Almost surely, 220535340153 is an apocalyptic number.

It is an amenable number.

20535340153 is a deficient number, since it is larger than the sum of its proper divisors (289230215).

20535340153 is an equidigital number, since it uses as much as digits as its factorization.

20535340153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 289230214.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 20535340153 its reverse (35104353502), we get a palindrome (55639693655).

The spelling of 20535340153 in words is "twenty billion, five hundred thirty-five million, three hundred forty thousand, one hundred fifty-three".

Divisors: 1 71 289230143 20535340153