Base | Representation |
---|---|
bin | 1001010101110111100000… |
… | …00100111101110100101011 |
3 | 2200201211221102112112210021 |
4 | 10222323300010331310223 |
5 | 10143032131212134430 |
6 | 111405042240501311 |
7 | 4220102552135245 |
oct | 452736004756453 |
9 | 80654842475707 |
10 | 20542561443115 |
11 | 6600062433708 |
12 | 237935231a837 |
13 | b6020307727a |
14 | 51039dcd5095 |
15 | 25955c2b707a |
hex | 12aef013dd2b |
20542561443115 has 4 divisors (see below), whose sum is σ = 24651073731744. Its totient is φ = 16434049154488.
The previous prime is 20542561443083. The next prime is 20542561443121. The reversal of 20542561443115 is 51134416524502.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20542561443115 - 25 = 20542561443083 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2054256144307 + ... + 2054256144316.
It is an arithmetic number, because the mean of its divisors is an integer number (6162768432936).
Almost surely, 220542561443115 is an apocalyptic number.
20542561443115 is a deficient number, since it is larger than the sum of its proper divisors (4108512288629).
20542561443115 is an equidigital number, since it uses as much as digits as its factorization.
20542561443115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4108512288628.
The product of its (nonzero) digits is 576000, while the sum is 43.
Adding to 20542561443115 its reverse (51134416524502), we get a palindrome (71676977967617).
The spelling of 20542561443115 in words is "twenty trillion, five hundred forty-two billion, five hundred sixty-one million, four hundred forty-three thousand, one hundred fifteen".
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