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2100104112313 = 4135150787263
BaseRepresentation
bin11110100011110111111…
…101011010100010111001
321102202201212101122110101
4132203313331122202321
5233402003123043223
64244435143315401
7304504352264014
oct36436775324271
97382655348411
102100104112313
1173a716027019
1229b02074bb61
131230677c731c
147390769237b
15399664304ad
hex1e8f7f5a8b9

2100104112313 has 4 divisors (see below), whose sum is σ = 2100154940928. Its totient is φ = 2100053283700.

The previous prime is 2100104112251. The next prime is 2100104112349. The reversal of 2100104112313 is 3132114010012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2100104112313 - 225 = 2100070557881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2100104112013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25352281 + ... + 25434982.

It is an arithmetic number, because the mean of its divisors is an integer number (525038735232).

Almost surely, 22100104112313 is an apocalyptic number.

It is an amenable number.

2100104112313 is a deficient number, since it is larger than the sum of its proper divisors (50828615).

2100104112313 is an equidigital number, since it uses as much as digits as its factorization.

2100104112313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50828614.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2100104112313 its reverse (3132114010012), we get a palindrome (5232218122325).

The spelling of 2100104112313 in words is "two trillion, one hundred billion, one hundred four million, one hundred twelve thousand, three hundred thirteen".

Divisors: 1 41351 50787263 2100104112313