Base | Representation |
---|---|
bin | 111110100101101… |
… | …0111110011111001 |
3 | 12102100202211000220 |
4 | 1331023113303321 |
5 | 13300113224423 |
6 | 544221050253 |
7 | 103020560031 |
oct | 17513276371 |
9 | 5370684026 |
10 | 2100133113 |
11 | 98851a101 |
12 | 4a73b6989 |
13 | 276136620 |
14 | 15ccc28c1 |
15 | c45919e3 |
hex | 7d2d7cf9 |
2100133113 has 16 divisors (see below), whose sum is σ = 3024542976. Its totient is φ = 1288546560.
The previous prime is 2100133093. The next prime is 2100133117. The reversal of 2100133113 is 3113310012.
It is a de Polignac number, because none of the positive numbers 2k-2100133113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2100133092 and 2100133101.
It is not an unprimeable number, because it can be changed into a prime (2100133117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66753 + ... + 93038.
It is an arithmetic number, because the mean of its divisors is an integer number (189033936).
Almost surely, 22100133113 is an apocalyptic number.
It is an amenable number.
2100133113 is a deficient number, since it is larger than the sum of its proper divisors (924409863).
2100133113 is a wasteful number, since it uses less digits than its factorization.
2100133113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 160144.
The product of its (nonzero) digits is 54, while the sum is 15.
The square root of 2100133113 is about 45827.2093084447. The cubic root of 2100133113 is about 1280.6062218340.
Adding to 2100133113 its reverse (3113310012), we get a palindrome (5213443125).
The spelling of 2100133113 in words is "two billion, one hundred million, one hundred thirty-three thousand, one hundred thirteen".
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