Base | Representation |
---|---|
bin | 11110100011111010110… |
… | …001000101110111110011 |
3 | 21102202212011000122012211 |
4 | 132203322301011313303 |
5 | 233402102202313210 |
6 | 4244443545032551 |
7 | 304505463526303 |
oct | 36437261056763 |
9 | 7382764018184 |
10 | 2100151213555 |
11 | 73a73a67796a |
12 | 29b034485757 |
13 | 1230744a9195 |
14 | 7390da33603 |
15 | 3996a63638a |
hex | 1e8fac45df3 |
2100151213555 has 8 divisors (see below), whose sum is σ = 2523251109744. Its totient is φ = 1678074535200.
The previous prime is 2100151213519. The next prime is 2100151213609. The reversal of 2100151213555 is 5553121510012.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2100151213555 - 223 = 2100142824947 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 255799941 + ... + 255808150.
It is an arithmetic number, because the mean of its divisors is an integer number (315406388718).
Almost surely, 22100151213555 is an apocalyptic number.
2100151213555 is a deficient number, since it is larger than the sum of its proper divisors (423099896189).
2100151213555 is an equidigital number, since it uses as much as digits as its factorization.
2100151213555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 511608917.
The product of its (nonzero) digits is 7500, while the sum is 31.
Adding to 2100151213555 its reverse (5553121510012), we get a palindrome (7653272723567).
The spelling of 2100151213555 in words is "two trillion, one hundred billion, one hundred fifty-one million, two hundred thirteen thousand, five hundred fifty-five".
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