Search a number
-
+
2100151213555 = 5821511608091
BaseRepresentation
bin11110100011111010110…
…001000101110111110011
321102202212011000122012211
4132203322301011313303
5233402102202313210
64244443545032551
7304505463526303
oct36437261056763
97382764018184
102100151213555
1173a73a67796a
1229b034485757
131230744a9195
147390da33603
153996a63638a
hex1e8fac45df3

2100151213555 has 8 divisors (see below), whose sum is σ = 2523251109744. Its totient is φ = 1678074535200.

The previous prime is 2100151213519. The next prime is 2100151213609. The reversal of 2100151213555 is 5553121510012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2100151213555 - 223 = 2100142824947 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 255799941 + ... + 255808150.

It is an arithmetic number, because the mean of its divisors is an integer number (315406388718).

Almost surely, 22100151213555 is an apocalyptic number.

2100151213555 is a deficient number, since it is larger than the sum of its proper divisors (423099896189).

2100151213555 is an equidigital number, since it uses as much as digits as its factorization.

2100151213555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 511608917.

The product of its (nonzero) digits is 7500, while the sum is 31.

Adding to 2100151213555 its reverse (5553121510012), we get a palindrome (7653272723567).

The spelling of 2100151213555 in words is "two trillion, one hundred billion, one hundred fifty-one million, two hundred thirteen thousand, five hundred fifty-five".

Divisors: 1 5 821 4105 511608091 2558040455 420030242711 2100151213555