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2100213122003 = 19110537532737
BaseRepresentation
bin11110100011111110011…
…101010000001111010011
321102210000110111220122022
4132203332131100033103
5233402214024401003
64244454040002055
7304510144662353
oct36437635201723
97383013456568
102100213122003
1173a771611677
1229b05116032b
131230842739b9
1473917d4ab63
1539970cb4738
hex1e8fe7503d3

2100213122003 has 4 divisors (see below), whose sum is σ = 2210750654760. Its totient is φ = 1989675589248.

The previous prime is 2100213121999. The next prime is 2100213122009. The reversal of 2100213122003 is 3002213120012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2100213122003 - 22 = 2100213121999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2100213122009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55268766350 + ... + 55268766387.

It is an arithmetic number, because the mean of its divisors is an integer number (552687663690).

Almost surely, 22100213122003 is an apocalyptic number.

2100213122003 is a deficient number, since it is larger than the sum of its proper divisors (110537532757).

2100213122003 is a wasteful number, since it uses less digits than its factorization.

2100213122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110537532756.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2100213122003 its reverse (3002213120012), we get a palindrome (5102426242015).

The spelling of 2100213122003 in words is "two trillion, one hundred billion, two hundred thirteen million, one hundred twenty-two thousand, three".

Divisors: 1 19 110537532737 2100213122003