Base | Representation |
---|---|
bin | 11110100011111110011… |
… | …101010000001111010011 |
3 | 21102210000110111220122022 |
4 | 132203332131100033103 |
5 | 233402214024401003 |
6 | 4244454040002055 |
7 | 304510144662353 |
oct | 36437635201723 |
9 | 7383013456568 |
10 | 2100213122003 |
11 | 73a771611677 |
12 | 29b05116032b |
13 | 1230842739b9 |
14 | 73917d4ab63 |
15 | 39970cb4738 |
hex | 1e8fe7503d3 |
2100213122003 has 4 divisors (see below), whose sum is σ = 2210750654760. Its totient is φ = 1989675589248.
The previous prime is 2100213121999. The next prime is 2100213122009. The reversal of 2100213122003 is 3002213120012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2100213122003 - 22 = 2100213121999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2100213122009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55268766350 + ... + 55268766387.
It is an arithmetic number, because the mean of its divisors is an integer number (552687663690).
Almost surely, 22100213122003 is an apocalyptic number.
2100213122003 is a deficient number, since it is larger than the sum of its proper divisors (110537532757).
2100213122003 is a wasteful number, since it uses less digits than its factorization.
2100213122003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110537532756.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 2100213122003 its reverse (3002213120012), we get a palindrome (5102426242015).
The spelling of 2100213122003 in words is "two trillion, one hundred billion, two hundred thirteen million, one hundred twenty-two thousand, three".
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