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2100343000411 = 20899100499689
BaseRepresentation
bin11110100100000110001…
…100101100110101011011
321102210100111220102022201
4132210012030230311123
5233403000302003121
64244514555431031
7304513312635535
oct36440614546533
97383314812281
102100343000411
1173a8289601a7
1229b088755477
131230a5149026
147392b2b8855
153997c3bbe91
hex1e90632cd5b

2100343000411 has 4 divisors (see below), whose sum is σ = 2100443521000. Its totient is φ = 2100242479824.

The previous prime is 2100343000409. The next prime is 2100343000433. The reversal of 2100343000411 is 1140003430012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2100343000411 - 21 = 2100343000409 is a prime.

It is a super-2 number, since 2×21003430004112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2100343000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50228946 + ... + 50270743.

It is an arithmetic number, because the mean of its divisors is an integer number (525110880250).

Almost surely, 22100343000411 is an apocalyptic number.

2100343000411 is a deficient number, since it is larger than the sum of its proper divisors (100520589).

2100343000411 is a wasteful number, since it uses less digits than its factorization.

2100343000411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100520588.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 2100343000411 its reverse (1140003430012), we get a palindrome (3240346430423).

The spelling of 2100343000411 in words is "two trillion, one hundred billion, three hundred forty-three million, four hundred eleven", and thus it is an aban number.

Divisors: 1 20899 100499689 2100343000411