Base | Representation |
---|---|
bin | 11110100100000110001… |
… | …100101100110101011011 |
3 | 21102210100111220102022201 |
4 | 132210012030230311123 |
5 | 233403000302003121 |
6 | 4244514555431031 |
7 | 304513312635535 |
oct | 36440614546533 |
9 | 7383314812281 |
10 | 2100343000411 |
11 | 73a8289601a7 |
12 | 29b088755477 |
13 | 1230a5149026 |
14 | 7392b2b8855 |
15 | 3997c3bbe91 |
hex | 1e90632cd5b |
2100343000411 has 4 divisors (see below), whose sum is σ = 2100443521000. Its totient is φ = 2100242479824.
The previous prime is 2100343000409. The next prime is 2100343000433. The reversal of 2100343000411 is 1140003430012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2100343000411 - 21 = 2100343000409 is a prime.
It is a super-2 number, since 2×21003430004112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2100343000111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50228946 + ... + 50270743.
It is an arithmetic number, because the mean of its divisors is an integer number (525110880250).
Almost surely, 22100343000411 is an apocalyptic number.
2100343000411 is a deficient number, since it is larger than the sum of its proper divisors (100520589).
2100343000411 is a wasteful number, since it uses less digits than its factorization.
2100343000411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100520588.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 2100343000411 its reverse (1140003430012), we get a palindrome (3240346430423).
The spelling of 2100343000411 in words is "two trillion, one hundred billion, three hundred forty-three million, four hundred eleven", and thus it is an aban number.
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