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21004203200315 = 54200840640063
BaseRepresentation
bin1001100011010011011000…
…00100100000111100111011
32202100222112000221122000112
410301221230010200330323
510223113102004402230
6112401110413454535
74265334510261146
oct461515404407473
982328460848015
1021004203200315
1167689181455a5
1224329091a144b
13b948c3308b4a
145288749d105d
1526657a60ed95
hex131a6c120f3b

21004203200315 has 4 divisors (see below), whose sum is σ = 25205043840384. Its totient is φ = 16803362560248.

The previous prime is 21004203200273. The next prime is 21004203200317. The reversal of 21004203200315 is 51300230240012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21004203200315 - 220 = 21004202151739 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21004203200317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2100420320027 + ... + 2100420320036.

It is an arithmetic number, because the mean of its divisors is an integer number (6301260960096).

Almost surely, 221004203200315 is an apocalyptic number.

21004203200315 is a deficient number, since it is larger than the sum of its proper divisors (4200840640069).

21004203200315 is an equidigital number, since it uses as much as digits as its factorization.

21004203200315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4200840640068.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 21004203200315 its reverse (51300230240012), we get a palindrome (72304433440327).

The spelling of 21004203200315 in words is "twenty-one trillion, four billion, two hundred three million, two hundred thousand, three hundred fifteen".

Divisors: 1 5 4200840640063 21004203200315