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210103113131 = 472344485097
BaseRepresentation
bin1100001110101100011…
…1110001010110101011
3202002022110002000020122
43003223013301112223
511420242344110011
6240304154513455
721115356665222
oct3035307612653
9662273060218
10210103113131
118111680367a
123487713588b
1316a744a0122
14a251c05cb9
1556ea3ee3db
hex30eb1f15ab

210103113131 has 4 divisors (see below), whose sum is σ = 210147602952. Its totient is φ = 210058623312.

The previous prime is 210103113127. The next prime is 210103113133. The reversal of 210103113131 is 131311301012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 210103113131 - 22 = 210103113127 is a prime.

It is a super-2 number, since 2×2101031131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (210103113133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22237826 + ... + 22247271.

It is an arithmetic number, because the mean of its divisors is an integer number (52536900738).

Almost surely, 2210103113131 is an apocalyptic number.

210103113131 is a deficient number, since it is larger than the sum of its proper divisors (44489821).

210103113131 is an equidigital number, since it uses as much as digits as its factorization.

210103113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44489820.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 210103113131 its reverse (131311301012), we get a palindrome (341414414143).

The spelling of 210103113131 in words is "two hundred ten billion, one hundred three million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 4723 44485097 210103113131