Base | Representation |
---|---|
bin | 11110100111100000111… |
… | …010100000110110000011 |
3 | 21110010211020121102021012 |
4 | 132213200322200312003 |
5 | 233433004141134021 |
6 | 4250323040351135 |
7 | 305003250453113 |
oct | 36474072406603 |
9 | 7403736542235 |
10 | 2104012443011 |
11 | 741341199796 |
12 | 29b9316154ab |
13 | 12353b43103b |
14 | 73b98783043 |
15 | 39ae45e935b |
hex | 1e9e0ea0d83 |
2104012443011 has 4 divisors (see below), whose sum is σ = 2106520206000. Its totient is φ = 2101504680024.
The previous prime is 2104012442989. The next prime is 2104012443047. The reversal of 2104012443011 is 1103442104012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2104012443011 - 238 = 1829134536067 is a prime.
It is a super-2 number, since 2×21040124430112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2104012442011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1253880236 + ... + 1253881913.
It is an arithmetic number, because the mean of its divisors is an integer number (526630051500).
Almost surely, 22104012443011 is an apocalyptic number.
2104012443011 is a deficient number, since it is larger than the sum of its proper divisors (2507762989).
2104012443011 is an equidigital number, since it uses as much as digits as its factorization.
2104012443011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2507762988.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 2104012443011 its reverse (1103442104012), we get a palindrome (3207454547023).
The spelling of 2104012443011 in words is "two trillion, one hundred four billion, twelve million, four hundred forty-three thousand, eleven".
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