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2104110153 = 32307761531
BaseRepresentation
bin111110101101010…
…0010110001001001
312102122020212111200
41331122202301021
513302123011103
6544442214413
7103066432635
oct17532426111
95378225450
102104110153
1198a796112
124a87b4409
13276bc98c2
1415d639dc5
15c4aca0a3
hex7d6a2c49

2104110153 has 12 divisors (see below), whose sum is σ = 3049174128. Its totient is φ = 1398169080.

The previous prime is 2104110133. The next prime is 2104110157. The reversal of 2104110153 is 3510114012.

It is not a de Polignac number, because 2104110153 - 25 = 2104110121 is a prime.

It is a super-3 number, since 3×21041101533 (a number of 29 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (2104110157) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 378003 + ... + 383528.

It is an arithmetic number, because the mean of its divisors is an integer number (254097844).

Almost surely, 22104110153 is an apocalyptic number.

It is an amenable number.

2104110153 is a deficient number, since it is larger than the sum of its proper divisors (945063975).

2104110153 is a wasteful number, since it uses less digits than its factorization.

2104110153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 761844 (or 761841 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

The square root of 2104110153 is about 45870.5804737634. The cubic root of 2104110153 is about 1281.4140770782.

Adding to 2104110153 its reverse (3510114012), we get a palindrome (5614224165).

The spelling of 2104110153 in words is "two billion, one hundred four million, one hundred ten thousand, one hundred fifty-three".

Divisors: 1 3 9 307 921 2763 761531 2284593 6853779 233790017 701370051 2104110153