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21050201115 = 325467782247
BaseRepresentation
bin10011100110101100…
…001001010000011011
32000100000200000100100
4103212230021100123
5321102322413430
613400442510443
71343433520506
oct234654112033
960300600310
1021050201115
118a22320729
1240b5805423
131ca6140908
14103998013d
15833066960
hex4e6b0941b

21050201115 has 12 divisors (see below), whose sum is σ = 36487015344. Its totient is φ = 11226773904.

The previous prime is 21050201113. The next prime is 21050201119. The reversal of 21050201115 is 51110205012.

It is not a de Polignac number, because 21050201115 - 21 = 21050201113 is a prime.

It is a super-2 number, since 2×210502011152 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (21050201113) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 233891079 + ... + 233891168.

It is an arithmetic number, because the mean of its divisors is an integer number (3040584612).

Almost surely, 221050201115 is an apocalyptic number.

21050201115 is a deficient number, since it is larger than the sum of its proper divisors (15436814229).

21050201115 is a wasteful number, since it uses less digits than its factorization.

21050201115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467782258 (or 467782255 counting only the distinct ones).

The product of its (nonzero) digits is 100, while the sum is 18.

Adding to 21050201115 its reverse (51110205012), we get a palindrome (72160406127).

It can be divided in two parts, 21050201 and 115, that added together give a triangular number (21050316 = T6488).

The spelling of 21050201115 in words is "twenty-one billion, fifty million, two hundred one thousand, one hundred fifteen".

Divisors: 1 3 5 9 15 45 467782247 1403346741 2338911235 4210040223 7016733705 21050201115