211001030113 has 4 divisors (see below), whose sum is σ = 220174987968. Its totient is φ = 201827072260.

The previous prime is 211001030069. The next prime is 211001030131. The reversal of 211001030113 is 311030100112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211001030113 - 2⁹ = 211001029601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211001030093 and 211001030102.

It is not an unprimeable number, because it can be changed into a prime (211001030153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4586978893 + ... + 4586978938.

It is an arithmetic number, because the mean of its divisors is an integer number (55043746992).

Almost surely, 2^211001030113 is an apocalyptic number.

211001030113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

211001030113 is a deficient number, since it is larger than the sum of its proper divisors (9173957855).

211001030113 is an equidigital number, since it uses as much as digits as its factorization.

211001030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9173957854.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 211001030113 its reverse (311030100112), we get a palindrome (522031130225).

The spelling of 211001030113 in words is "two hundred eleven billion, one million, thirty thousand, one hundred thirteen".