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21100313000113 = 43646975854839
BaseRepresentation
bin1001100110000110011001…
…01010010011100010110001
32202201011121002111022211021
410303003030222103202301
510231201420112000423
6112513203332215441
74305306266142124
oct463031452234261
982634532438737
1021100313000113
1167a5657671706
12244947016a581
13ba099bb8c079
1452d3911203bb
15268d0306295d
hex1330cca938b1

21100313000113 has 8 divisors (see below), whose sum is σ = 21594355851200. Its totient is φ = 20606421871728.

The previous prime is 21100313000071. The next prime is 21100313000147. The reversal of 21100313000113 is 31100031300112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-21100313000113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21100313007113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37649253 + ... + 38205586.

It is an arithmetic number, because the mean of its divisors is an integer number (2699294481400).

Almost surely, 221100313000113 is an apocalyptic number.

It is an amenable number.

21100313000113 is a deficient number, since it is larger than the sum of its proper divisors (494042851087).

21100313000113 is an equidigital number, since it uses as much as digits as its factorization.

21100313000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75861351.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 21100313000113 its reverse (31100031300112), we get a palindrome (52200344300225).

The spelling of 21100313000113 in words is "twenty-one trillion, one hundred billion, three hundred thirteen million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 43 6469 278167 75854839 3261758077 490704953491 21100313000113