211010300000131 has 4 divisors (see below), whose sum is σ = 223422670588392. Its totient is φ = 198597929411872.

The previous prime is 211010300000099. The next prime is 211010300000153. The reversal of 211010300000131 is 131000003010112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211010300000131 - 2⁵ = 211010300000099 is a prime.

It is a super-2 number, since 2×211010300000131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211010300000161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6206185294105 + ... + 6206185294138.

It is an arithmetic number, because the mean of its divisors is an integer number (55855667647098).

Almost surely, 2^{211010300000131} is an apocalyptic number.

211010300000131 is a deficient number, since it is larger than the sum of its proper divisors (12412370588261).

211010300000131 is a wasteful number, since it uses less digits than its factorization.

211010300000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12412370588260.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 211010300000131 its reverse (131000003010112), we get a palindrome (342010303010243).

The spelling of 211010300000131 in words is "two hundred eleven trillion, ten billion, three hundred million, one hundred thirty-one", and thus it is an aban number.