Base | Representation |
---|---|
bin | 1100010010000101001… |
… | …1110100011011011011 |
3 | 202011122210202111101110 |
4 | 3010201103310123123 |
5 | 11424123113203430 |
6 | 240534312351403 |
7 | 21150036312144 |
oct | 3044123643333 |
9 | 664583674343 |
10 | 211012241115 |
11 | 815429aaa15 |
12 | 34a8b6a5563 |
13 | 16b8a941490 |
14 | a2da85aacb |
15 | 57501307b0 |
hex | 31214f46db |
211012241115 has 16 divisors (see below), whose sum is σ = 363590323488. Its totient is φ = 103882949376.
The previous prime is 211012241093. The next prime is 211012241129. The reversal of 211012241115 is 511142210112.
211012241115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 211012241115 - 27 = 211012240987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211012241091 and 211012241100.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 541056834 + ... + 541057223.
It is an arithmetic number, because the mean of its divisors is an integer number (22724395218).
Almost surely, 2211012241115 is an apocalyptic number.
211012241115 is a deficient number, since it is larger than the sum of its proper divisors (152578082373).
211012241115 is a wasteful number, since it uses less digits than its factorization.
211012241115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1082114078.
The product of its (nonzero) digits is 160, while the sum is 21.
Adding to 211012241115 its reverse (511142210112), we get a palindrome (722154451227).
The spelling of 211012241115 in words is "two hundred eleven billion, twelve million, two hundred forty-one thousand, one hundred fifteen".
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