21101411132433 has 12 divisors (see below), whose sum is σ = 30514334569680. Its totient is φ = 14051675811096.

The previous prime is 21101411132419. The next prime is 21101411132509. The reversal of 21101411132433 is 33423111410112.

21101411132433 is a `hidden beast` number, since 2 + 1 + 1 + 0 + 1 + 411 + 1 + 3 + 243 + 3 = 666.

It is not a de Polignac number, because 21101411132433 - 2⁵ = 21101411132401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21101411132397 and 21101411132406.

It is not an unprimeable number, because it can be changed into a prime (21101411131433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1327625823 + ... + 1327641716.

It is an arithmetic number, because the mean of its divisors is an integer number (2542861214140).

Almost surely, 2^{21101411132433} is an apocalyptic number.

It is an amenable number.

21101411132433 is a deficient number, since it is larger than the sum of its proper divisors (9412923437247).

21101411132433 is a wasteful number, since it uses less digits than its factorization.

21101411132433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2655268428 (or 2655268425 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 21101411132433 its reverse (33423111410112), we get a palindrome (54524522542545).

The spelling of 21101411132433 in words is "twenty-one trillion, one hundred one billion, four hundred eleven million, one hundred thirty-two thousand, four hundred thirty-three".