21102000113 has 4 divisors (see below), whose sum is σ = 21105612528. Its totient is φ = 21098387700.

The previous prime is 21102000097. The next prime is 21102000149. The reversal of 21102000113 is 31100020112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21102000113 - 2⁴ = 21102000097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 21102000094 and 21102000103.

It is not an unprimeable number, because it can be changed into a prime (21102000163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1797431 + ... + 1809132.

It is an arithmetic number, because the mean of its divisors is an integer number (5276403132).

Almost surely, 2^21102000113 is an apocalyptic number.

It is an amenable number.

21102000113 is a deficient number, since it is larger than the sum of its proper divisors (3612415).

21102000113 is an equidigital number, since it uses as much as digits as its factorization.

21102000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3612414.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 21102000113 its reverse (31100020112), we get a palindrome (52202020225).

The spelling of 21102000113 in words is "twenty-one billion, one hundred two million, one hundred thirteen", and thus it is an aban number.