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21102320113 = 7191045715173
BaseRepresentation
bin10011101001110010…
…111101100111110001
32000110122201221011121
4103221302331213301
5321204143220423
613405543542241
71344635522110
oct235162754761
960418657147
1021102320113
118a49789486
12410b15a981
131cb3b8b664
141042869c77
1583790e45d
hex4e9cbd9f1

21102320113 has 16 divisors (see below), whose sum is σ = 25390350720. Its totient is φ = 17132950656.

The previous prime is 21102320111. The next prime is 21102320191. The reversal of 21102320113 is 31102320112.

It is a cyclic number.

It is not a de Polignac number, because 21102320113 - 21 = 21102320111 is a prime.

It is a super-3 number, since 3×211023201133 (a number of 32 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (21102320111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1383195 + ... + 1398367.

It is an arithmetic number, because the mean of its divisors is an integer number (1586896920).

Almost surely, 221102320113 is an apocalyptic number.

It is an amenable number.

21102320113 is a deficient number, since it is larger than the sum of its proper divisors (4288030607).

21102320113 is a wasteful number, since it uses less digits than its factorization.

21102320113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25656.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 21102320113 its reverse (31102320112), we get a palindrome (52204640225).

Subtracting 21102320113 from its reverse (31102320112), we obtain a palindrome (9999999999).

The spelling of 21102320113 in words is "twenty-one billion, one hundred two million, three hundred twenty thousand, one hundred thirteen".

Divisors: 1 7 19 133 10457 15173 73199 106211 198683 288287 1390781 2018009 158664061 1110648427 3014617159 21102320113