2110333131113 has 4 divisors (see below), whose sum is σ = 2112404116560. Its totient is φ = 2108262145668.

The previous prime is 2110333131097. The next prime is 2110333131157. The reversal of 2110333131113 is 3111313330112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2110333131113 - 2⁴ = 2110333131097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2110333131013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1035491195 + ... + 1035493232.

It is an arithmetic number, because the mean of its divisors is an integer number (528101029140).

Almost surely, 2^{2110333131113} is an apocalyptic number.

It is an amenable number.

2110333131113 is a deficient number, since it is larger than the sum of its proper divisors (2070985447).

2110333131113 is a wasteful number, since it uses less digits than its factorization.

2110333131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2070985446.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 2110333131113 its reverse (3111313330112), we get a palindrome (5221646461225).

The spelling of 2110333131113 in words is "two trillion, one hundred ten billion, three hundred thirty-three million, one hundred thirty-one thousand, one hundred thirteen".