Base | Representation |
---|---|
bin | 101111111111000010110010… |
… | …010001101111111100101001 |
3 | 1000200020021102120210211212010 |
4 | 233333002302101233330221 |
5 | 210130141423014203140 |
6 | 2024502400311310133 |
7 | 62311113266340615 |
oct | 5777026221577451 |
9 | 1020207376724763 |
10 | 211040504053545 |
11 | 612758587a6181 |
12 | 1b80509197b349 |
13 | 909b05a00960a |
14 | 3a185b4696345 |
15 | 195e9ab5e9880 |
hex | bff0b246ff29 |
211040504053545 has 16 divisors (see below), whose sum is σ = 339686751438720. Its totient is φ = 111880953844224.
The previous prime is 211040504053501. The next prime is 211040504053571. The reversal of 211040504053545 is 545350405040112.
It is not a de Polignac number, because 211040504053545 - 28 = 211040504053289 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42123850600 + ... + 42123855609.
It is an arithmetic number, because the mean of its divisors is an integer number (21230421964920).
Almost surely, 2211040504053545 is an apocalyptic number.
It is an amenable number.
211040504053545 is a deficient number, since it is larger than the sum of its proper divisors (128646247385175).
211040504053545 is a wasteful number, since it uses less digits than its factorization.
211040504053545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84247706384.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 211040504053545 its reverse (545350405040112), we get a palindrome (756390909093657).
The spelling of 211040504053545 in words is "two hundred eleven trillion, forty billion, five hundred four million, fifty-three thousand, five hundred forty-five".
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