2110444113 has 4 divisors (see below), whose sum is σ = 2813925488. Its totient is φ = 1406962740.

The previous prime is 2110444109. The next prime is 2110444117. The reversal of 2110444113 is 3114440112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (2110444109) and next prime (2110444117).

It is not a de Polignac number, because 2110444113 - 2² = 2110444109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2110444113.

It is not an unprimeable number, because it can be changed into a prime (2110444117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351740683 + ... + 351740688.

It is an arithmetic number, because the mean of its divisors is an integer number (703481372).

Almost surely, 2^2110444113 is an apocalyptic number.

It is an amenable number.

2110444113 is a deficient number, since it is larger than the sum of its proper divisors (703481375).

2110444113 is an equidigital number, since it uses as much as digits as its factorization.

2110444113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 703481374.

The product of its (nonzero) digits is 384, while the sum is 21.

The square root of 2110444113 is about 45939.5702309022. The cubic root of 2110444113 is about 1282.6985939324.

Adding to 2110444113 its reverse (3114440112), we get a palindrome (5224884225).

The spelling of 2110444113 in words is "two billion, one hundred ten million, four hundred forty-four thousand, one hundred thirteen".