211100110130011 has 4 divisors (see below), whose sum is σ = 212046747395392. Its totient is φ = 210153472864632.

The previous prime is 211100110129973. The next prime is 211100110130017. The reversal of 211100110130011 is 110031011001112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211100110130011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211100110129973 and 211100110130000.

It is not an unprimeable number, because it can be changed into a prime (211100110130017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 473318632356 + ... + 473318632801.

It is an arithmetic number, because the mean of its divisors is an integer number (53011686848848).

Almost surely, 2^{211100110130011} is an apocalyptic number.

211100110130011 is a deficient number, since it is larger than the sum of its proper divisors (946637265381).

211100110130011 is an equidigital number, since it uses as much as digits as its factorization.

211100110130011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 946637265380.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 211100110130011 its reverse (110031011001112), we get a palindrome (321131121131123).

The spelling of 211100110130011 in words is "two hundred eleven trillion, one hundred billion, one hundred ten million, one hundred thirty thousand, eleven".