21110113013441 has 4 divisors (see below), whose sum is σ = 21155316682032. Its totient is φ = 21064909344852.

The previous prime is 21110113013357. The next prime is 21110113013447. The reversal of 21110113013441 is 14431031101112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21110113013441 is a prime.

It is a super-3 number, since 3×21110113013441³ (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (21110113013447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22601833595 + ... + 22601834528.

It is an arithmetic number, because the mean of its divisors is an integer number (5288829170508).

Almost surely, 2^{21110113013441} is an apocalyptic number.

It is an amenable number.

21110113013441 is a deficient number, since it is larger than the sum of its proper divisors (45203668591).

21110113013441 is an equidigital number, since it uses as much as digits as its factorization.

21110113013441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45203668590.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 21110113013441 its reverse (14431031101112), we get a palindrome (35541144114553).

The spelling of 21110113013441 in words is "twenty-one trillion, one hundred ten billion, one hundred thirteen million, thirteen thousand, four hundred forty-one".