Base | Representation |
---|---|
bin | 1001100110011000101011… |
… | …10111100000001011111011 |
3 | 2202202002221100001001121102 |
4 | 10303030111313200023323 |
5 | 10231332022032144011 |
6 | 112521505501002015 |
7 | 4306104504652610 |
oct | 463142567401373 |
9 | 82662840031542 |
10 | 21110131131131 |
11 | 67a9835757879 |
12 | 244b35025330b |
13 | ba18a4c9ca53 |
14 | 52da43060507 |
15 | 2691c9e9873b |
hex | 133315de02fb |
21110131131131 has 4 divisors (see below), whose sum is σ = 24125864149872. Its totient is φ = 18094398112392.
The previous prime is 21110131131127. The next prime is 21110131131137. The reversal of 21110131131131 is 13113113101112.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 21110131131131 - 22 = 21110131131127 is a prime.
It is a super-2 number, since 2×211101311311312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21110131131137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1507866509360 + ... + 1507866509373.
It is an arithmetic number, because the mean of its divisors is an integer number (6031466037468).
Almost surely, 221110131131131 is an apocalyptic number.
21110131131131 is a deficient number, since it is larger than the sum of its proper divisors (3015733018741).
21110131131131 is an equidigital number, since it uses as much as digits as its factorization.
21110131131131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3015733018740.
The product of its (nonzero) digits is 54, while the sum is 20.
Adding to 21110131131131 its reverse (13113113101112), we get a palindrome (34223244232243).
The spelling of 21110131131131 in words is "twenty-one trillion, one hundred ten billion, one hundred thirty-one million, one hundred thirty-one thousand, one hundred thirty-one".
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