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211103011313 = 309836813511
BaseRepresentation
bin1100010010011010111…
…0000101000111110001
3202011220010120002200122
43010212232011013301
511424314332330223
6240551314100025
721152220663245
oct3044656050761
9664803502618
10211103011313
118158a167a07
1234ab5b7a615
1316ba36a2b5c
14a308928425
1557580b05c8
hex3126b851f1

211103011313 has 4 divisors (see below), whose sum is σ = 211109855808. Its totient is φ = 211096166820.

The previous prime is 211103011309. The next prime is 211103011321. The reversal of 211103011313 is 313110301112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211103011313 - 22 = 211103011309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211103011291 and 211103011300.

It is not an unprimeable number, because it can be changed into a prime (211103011363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3375773 + ... + 3437738.

It is an arithmetic number, because the mean of its divisors is an integer number (52777463952).

Almost surely, 2211103011313 is an apocalyptic number.

It is an amenable number.

211103011313 is a deficient number, since it is larger than the sum of its proper divisors (6844495).

211103011313 is an equidigital number, since it uses as much as digits as its factorization.

211103011313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6844494.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 211103011313 its reverse (313110301112), we get a palindrome (524213312425).

The spelling of 211103011313 in words is "two hundred eleven billion, one hundred three million, eleven thousand, three hundred thirteen".

Divisors: 1 30983 6813511 211103011313