2111121000113 has 4 divisors (see below), whose sum is σ = 2179221677568. Its totient is φ = 2043020322660.

The previous prime is 2111121000049. The next prime is 2111121000119. The reversal of 2111121000113 is 3110001211112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111121000113 - 2⁶ = 2111121000049 is a prime.

It is a super-2 number, since 2×2111121000113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111121000119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34050338681 + ... + 34050338742.

It is an arithmetic number, because the mean of its divisors is an integer number (544805419392).

Almost surely, 2^{2111121000113} is an apocalyptic number.

It is an amenable number.

2111121000113 is a deficient number, since it is larger than the sum of its proper divisors (68100677455).

2111121000113 is an equidigital number, since it uses as much as digits as its factorization.

2111121000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68100677454.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 2111121000113 its reverse (3110001211112), we get a palindrome (5221122211225).

The spelling of 2111121000113 in words is "two trillion, one hundred eleven billion, one hundred twenty-one million, one hundred thirteen", and thus it is an aban number.