Base | Representation |
---|---|
bin | 10011101010010101… |
… | …001110101111001011 |
3 | 2000111021122022112101 |
4 | 103222111032233023 |
5 | 321213443144430 |
6 | 13410504254231 |
7 | 1345105054450 |
oct | 235225165713 |
9 | 60437568471 |
10 | 21111303115 |
11 | 8a53864551 |
12 | 4112171377 |
13 | 1cb59b5346 |
14 | 1043b27827 |
15 | 8385d5dca |
hex | 4ea54ebcb |
21111303115 has 16 divisors (see below), whose sum is σ = 29319137280. Its totient is φ = 14293075680.
The previous prime is 21111303077. The next prime is 21111303127. The reversal of 21111303115 is 51130311112.
It is not a de Polignac number, because 21111303115 - 27 = 21111302987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21111303092 and 21111303101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3814831 + ... + 3820360.
It is an arithmetic number, because the mean of its divisors is an integer number (1832446080).
Almost surely, 221111303115 is an apocalyptic number.
21111303115 is a deficient number, since it is larger than the sum of its proper divisors (8207834165).
21111303115 is an equidigital number, since it uses as much as digits as its factorization.
21111303115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7635282.
The product of its (nonzero) digits is 90, while the sum is 19.
Adding to 21111303115 its reverse (51130311112), we get a palindrome (72241614227).
The spelling of 21111303115 in words is "twenty-one billion, one hundred eleven million, three hundred three thousand, one hundred fifteen".
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