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2111131403 = 3168101013
BaseRepresentation
bin111110111010101…
…0100111100001011
312110010110120211222
41331311110330023
513310422201103
6545252512255
7103213215023
oct17565247413
95403416758
102111131403
119937512a7
124ab01b68b
132784b76a4
14160546a83
15c5515638
hex7dd54f0b

2111131403 has 4 divisors (see below), whose sum is σ = 2179232448. Its totient is φ = 2043030360.

The previous prime is 2111131361. The next prime is 2111131409. The reversal of 2111131403 is 3041311112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111131403 - 216 = 2111065867 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111131409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34050476 + ... + 34050537.

It is an arithmetic number, because the mean of its divisors is an integer number (544808112).

Almost surely, 22111131403 is an apocalyptic number.

2111131403 is a deficient number, since it is larger than the sum of its proper divisors (68101045).

2111131403 is an equidigital number, since it uses as much as digits as its factorization.

2111131403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68101044.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 2111131403 is about 45947.0499923553. The cubic root of 2111131403 is about 1282.8378205891.

Adding to 2111131403 its reverse (3041311112), we get a palindrome (5152442515).

The spelling of 2111131403 in words is "two billion, one hundred eleven million, one hundred thirty-one thousand, four hundred three".

Divisors: 1 31 68101013 2111131403