Base | Representation |
---|---|
bin | 1001100110011100101110… |
… | …01100111100010010010001 |
3 | 2202202022112120001102201201 |
4 | 10303032113030330102101 |
5 | 10231400443024341423 |
6 | 112522505053031201 |
7 | 4306212333436333 |
oct | 463162714742221 |
9 | 82668476042651 |
10 | 21112301012113 |
11 | 67aa749585543 |
12 | 244b856a85501 |
13 | ba1b5c6b71ac |
14 | 52dbab2db453 |
15 | 2692a57162ad |
hex | 13339733c491 |
21112301012113 has 4 divisors (see below), whose sum is σ = 21115393490160. Its totient is φ = 21109208534068.
The previous prime is 21112301012087. The next prime is 21112301012213. The reversal of 21112301012113 is 31121010321112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21112301012113 - 237 = 20974862058641 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21112301012213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1546228783 + ... + 1546242436.
It is an arithmetic number, because the mean of its divisors is an integer number (5278848372540).
Almost surely, 221112301012113 is an apocalyptic number.
It is an amenable number.
21112301012113 is a deficient number, since it is larger than the sum of its proper divisors (3092478047).
21112301012113 is an equidigital number, since it uses as much as digits as its factorization.
21112301012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3092478046.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 21112301012113 its reverse (31121010321112), we get a palindrome (52233311333225).
The spelling of 21112301012113 in words is "twenty-one trillion, one hundred twelve billion, three hundred one million, twelve thousand, one hundred thirteen".
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