Base | Representation |
---|---|
bin | 1001100110011100101110… |
… | …01101110111010111100011 |
3 | 2202202022112120111201200202 |
4 | 10303032113031313113203 |
5 | 10231400443110112430 |
6 | 112522505102135415 |
7 | 4306212335465021 |
oct | 463162715672743 |
9 | 82668476451622 |
10 | 21112301254115 |
11 | 67aa749730345 |
12 | 244b856b8156b |
13 | ba1b5c7703a6 |
14 | 52dbab361711 |
15 | 2692a5762d45 |
hex | 1333973775e3 |
21112301254115 has 4 divisors (see below), whose sum is σ = 25334761504944. Its totient is φ = 16889841003288.
The previous prime is 21112301254097. The next prime is 21112301254241. The reversal of 21112301254115 is 51145210321112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21112301254115 - 240 = 20012789626339 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2111230125407 + ... + 2111230125416.
It is an arithmetic number, because the mean of its divisors is an integer number (6333690376236).
Almost surely, 221112301254115 is an apocalyptic number.
21112301254115 is a deficient number, since it is larger than the sum of its proper divisors (4222460250829).
21112301254115 is an equidigital number, since it uses as much as digits as its factorization.
21112301254115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4222460250828.
The product of its (nonzero) digits is 2400, while the sum is 29.
Adding to 21112301254115 its reverse (51145210321112), we get a palindrome (72257511575227).
The spelling of 21112301254115 in words is "twenty-one trillion, one hundred twelve billion, three hundred one million, two hundred fifty-four thousand, one hundred fifteen".
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