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211130010033 = 3119595884829
BaseRepresentation
bin1100010010100001010…
…1000100100110110001
3202011222000100202222020
43010220111010212301
511424343240310113
6240554120502053
721152666321565
oct3045025044661
9664860322866
10211130010033
11815a34284a8
1234b0301a929
1316ba9166a27
14a30c3556a5
15575a645023
hex31285449b1

211130010033 has 8 divisors (see below), whose sum is σ = 281530267200. Its totient is φ = 140741546448.

The previous prime is 211130010011. The next prime is 211130010041. The reversal of 211130010033 is 330010031112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 211130010033 - 26 = 211130009969 is a prime.

It is a super-2 number, since 2×2111300100332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211130009994 and 211130010021.

It is not an unprimeable number, because it can be changed into a prime (211130010043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2906538 + ... + 2978291.

It is an arithmetic number, because the mean of its divisors is an integer number (35191283400).

Almost surely, 2211130010033 is an apocalyptic number.

It is an amenable number.

211130010033 is a deficient number, since it is larger than the sum of its proper divisors (70400257167).

211130010033 is a wasteful number, since it uses less digits than its factorization.

211130010033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5896791.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 211130010033 its reverse (330010031112), we get a palindrome (541140041145).

The spelling of 211130010033 in words is "two hundred eleven billion, one hundred thirty million, ten thousand, thirty-three".

Divisors: 1 3 11959 35877 5884829 17654487 70376670011 211130010033