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211130012433 = 3591192824929
BaseRepresentation
bin1100010010100001010…
…1000101001100010001
3202011222000100220021010
43010220111011030101
511424343240344213
6240554120521133
721152666331564
oct3045025051421
9664860326233
10211130012433
11815a342a28a
1234b030201a9
1316ba9167b52
14a30c3564db
15575a645ac3
hex3128545311

211130012433 has 8 divisors (see below), whose sum is σ = 286277983200. Its totient is φ = 138367691648.

The previous prime is 211130012363. The next prime is 211130012479. The reversal of 211130012433 is 334210031112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 211130012433 - 222 = 211125818129 is a prime.

It is not an unprimeable number, because it can be changed into a prime (211130012333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 596412288 + ... + 596412641.

It is an arithmetic number, because the mean of its divisors is an integer number (35784747900).

Almost surely, 2211130012433 is an apocalyptic number.

It is an amenable number.

211130012433 is a deficient number, since it is larger than the sum of its proper divisors (75147970767).

211130012433 is a wasteful number, since it uses less digits than its factorization.

211130012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192824991.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 211130012433 its reverse (334210031112), we get a palindrome (545340043545).

The spelling of 211130012433 in words is "two hundred eleven billion, one hundred thirty million, twelve thousand, four hundred thirty-three".

Divisors: 1 3 59 177 1192824929 3578474787 70376670811 211130012433