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2111300130003 = 32207318879343
BaseRepresentation
bin11110101110010011010…
…010110101010011010011
321110211122010200021102020
4132232103102311103103
5234042420313130003
64253530133022523
7305351662000011
oct36562322652323
97424563607366
102111300130003
117444409778a9
122a1226184a43
1312413021346c
147428a5c98b1
1539dbe2ddd53
hex1eb934b54d3

2111300130003 has 8 divisors (see below), whose sum is σ = 2816342366208. Its totient is φ = 1406895656904.

The previous prime is 2111300129993. The next prime is 2111300130007. The reversal of 2111300130003 is 3000310031112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2111300130003 - 213 = 2111300121811 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2111300130007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 159433051 + ... + 159446292.

It is an arithmetic number, because the mean of its divisors is an integer number (352042795776).

Almost surely, 22111300130003 is an apocalyptic number.

2111300130003 is a deficient number, since it is larger than the sum of its proper divisors (705042236205).

2111300130003 is a wasteful number, since it uses less digits than its factorization.

2111300130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318881553.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 2111300130003 its reverse (3000310031112), we get a palindrome (5111610161115).

The spelling of 2111300130003 in words is "two trillion, one hundred eleven billion, three hundred million, one hundred thirty thousand, three".

Divisors: 1 3 2207 6621 318879343 956638029 703766710001 2111300130003