Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1000101011000111001 |
3 | 202011222000100221101001 |
4 | 3010220111011120321 |
5 | 11424343240410431 |
6 | 240554120525001 |
7 | 21152666334130 |
oct | 3045025053071 |
9 | 664860327331 |
10 | 211130013241 |
11 | 815a342a954 |
12 | 34b03020761 |
13 | 16ba9168324 |
14 | a30c356917 |
15 | 575a645e61 |
hex | 3128545639 |
211130013241 has 4 divisors (see below), whose sum is σ = 241291443712. Its totient is φ = 180968582772.
The previous prime is 211130013187. The next prime is 211130013251. The reversal of 211130013241 is 142310031112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211130013241 - 27 = 211130013113 is a prime.
It is a super-2 number, since 2×2111300132412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211130013251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15080715225 + ... + 15080715238.
It is an arithmetic number, because the mean of its divisors is an integer number (60322860928).
Almost surely, 2211130013241 is an apocalyptic number.
It is an amenable number.
211130013241 is a deficient number, since it is larger than the sum of its proper divisors (30161430471).
211130013241 is an equidigital number, since it uses as much as digits as its factorization.
211130013241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30161430470.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 211130013241 its reverse (142310031112), we get a palindrome (353440044353).
The spelling of 211130013241 in words is "two hundred eleven billion, one hundred thirty million, thirteen thousand, two hundred forty-one".
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