Base | Representation |
---|---|
bin | 11110101110010011010… |
… | …111010010111100100011 |
3 | 21110211122012212201100120 |
4 | 132232103113102330203 |
5 | 234042421113100003 |
6 | 4253530214051323 |
7 | 305352004642050 |
oct | 36562327227443 |
9 | 7424565781316 |
10 | 2111301300003 |
11 | 7444415a6945 |
12 | 2a1226649b43 |
13 | 124130532b7c |
14 | 7428a812027 |
15 | 39dbe470853 |
hex | 1eb935d2f23 |
2111301300003 has 16 divisors (see below), whose sum is σ = 3226182658560. Its totient is φ = 1203097274496.
The previous prime is 2111301300001. The next prime is 2111301300029. The reversal of 2111301300003 is 3000031031112.
It is not a de Polignac number, because 2111301300003 - 21 = 2111301300001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2111301300001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 140017750 + ... + 140032827.
It is an arithmetic number, because the mean of its divisors is an integer number (201636416160).
Almost surely, 22111301300003 is an apocalyptic number.
2111301300003 is a deficient number, since it is larger than the sum of its proper divisors (1114881358557).
2111301300003 is a wasteful number, since it uses less digits than its factorization.
2111301300003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280050946.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 2111301300003 its reverse (3000031031112), we get a palindrome (5111332331115).
The spelling of 2111301300003 in words is "two trillion, one hundred eleven billion, three hundred one million, three hundred thousand, three".
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