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211131140243 = 450391468773
BaseRepresentation
bin1100010010100001100…
…1011000100010010011
3202011222002111012022212
43010220121120202103
511424344032441433
6240554201022335
721153012036632
oct3045031304223
9664862435285
10211131140243
11815a402a661
1234b034849ab
1316ba94712aa
14a30c56b519
15575a7b9d48
hex3128658893

211131140243 has 4 divisors (see below), whose sum is σ = 211132059408. Its totient is φ = 211130221080.

The previous prime is 211131140219. The next prime is 211131140249. The reversal of 211131140243 is 342041131112.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 211131140243 - 214 = 211131123859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211131140249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216005 + ... + 684777.

It is an arithmetic number, because the mean of its divisors is an integer number (52783014852).

Almost surely, 2211131140243 is an apocalyptic number.

211131140243 is a deficient number, since it is larger than the sum of its proper divisors (919165).

211131140243 is an equidigital number, since it uses as much as digits as its factorization.

211131140243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 919164.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 211131140243 its reverse (342041131112), we get a palindrome (553172271355).

The spelling of 211131140243 in words is "two hundred eleven billion, one hundred thirty-one million, one hundred forty thousand, two hundred forty-three".

Divisors: 1 450391 468773 211131140243